[Dnsmasq-discuss] Question about behaviour of '#' symbol

[Matus UHLAR - fantomas]

On 18.03.24 09:41, Elias LA via Dnsmasq-discuss wrote:
>In mydnsmasq.conffile, I have either one of two sets of rules:
>
># Set 1:
>
>no-resolv
>server=8.8.8.8
>
>server=/firebaseio.com/#
>address=/*.firebaseio.com/
>
># Set 2:
>
>no-resolv
>server=8.8.8.8
>
>server=/firebaseio.com/8.8.8.8
>address=/*.firebaseio.com/
>
> Running `dig firebaseio.com` using Set 1 gives local address, but using 
> `Set 2` give a valid server IP address.  Why does not the first set give a 
> valid IP?  Is not the rule `server=/firebaseio.com/#`supposed to fetch the 
> IP address from the "the standard servers" defined by `server=8.8.8.8`?

the dnsmasq documentation says in the "-S --local --server=" docs:

   The special server address '#' means, "use the  standard servers", so 
   --server=/google.com/1.2.3.4 --server=/www.google.com/# will send queries 
   for google.com and its subdomains to 1.2.3.4, except www.google.com (and 
   its subdo‐ mains) which will be forwarded as usual.

which usually means, use servers mentioned in /etc/resolv.conf for that 
domain.

note that when you already have:

server=8.8.8.8

it's useless to specify any domains to the same server

>server=/firebaseio.com/8.8.8.8

you can skip this line.

-- 
Matus UHLAR - fantomas, uhlar at fantomas.sk ; http://www.fantomas.sk/
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On the other hand, you have different fingers.